viscosity solution notes |numerical problem |fluid mechanic|episode-10|unit-2
FLUID MECHANIC
viscosity
unit-2
- NUMERICAL PROBLEM WITH SOLUTIONS
Q.if the dynamic viscosity of the liquid is 0.08 poise and specific gravity of the liquid 2.9 then determine the viscosity in stoke.
ANS=0.027 stoke
Q.viscosity of fluid with specific gravity 1.3 , measure- 0.0034( N-S/m2 ).Its kinematics viscosity in (m2/s)
ANS=2.6×10-6 (m2/s)
Q. IF the shear stress acted upon the particular layer 0.2542 N/m2 , then determine the dynamic viscosity in poise and kinematics viscosity in stoke when the specific gravity of the liquid 0.88,velocity gradient along the flow 0.2 sec^-1
ANS= dynamic viscosity=1.226 N-S/m2
kinematics viscosity=13.93 stokeNEXT
Q. A plate having area 1.6×106mm2 and the velocity of upper plate is 2 m/s relative to another stationary same plate and the gap between plate are filled by dynamic viscosity of the oil 3 poise and the distance between plate are 5 mm then determine require force and power to maintain this speed.
ANS=F=192 N
P=384 N-m/s
Q. in two plate system which is having square in shape and side of the plate 60 cm.if the upper plate is moving with the velocity 2.5 m/s relative to another stationary same plate and gap between plate 12.5 mm and required 98.1 N force to maintain this speed then determine (1) dynamic viscosity in poise
(2) kinematics viscosity in stoke,assume density of oil-980 kg/m3
ANS=13.6 poise,13.90 stokeNEXT
ANS=Y=0.1m
Q.If the velocity relation u=5sin(5πy) where,u=velocity in m/sec and y=position in m, dynamic viscosity of the oil 0.8 N-S/m^2 then determine the position,where shear stress become zerO
Q.(IES) IF the velocity distribution is given by u=(2/3)y-y2 where y is the position in metre and u is velocity in m/sec,if the dynamic viscosity of the oil 8.63 poise then determine the
(1) velocity gradient in terms of y
(2) velocity gradient at y=0 and y=0.15m
(3) shear stress at y=0 and y=0.15m
ANS=1.(du/dy)=2/3-2y
2.(du/dy)=2/3,when y=0
(du/dy)=0.36 sec-1
3.At y=0,shear stress=0.57 N/m3
At y=0.15,shear stress=0.31068 N/m3NEXT
Q. determine the value of K when velocity distribution u=(3/4)y-y2where u=velocity in m/sec, y is the position in metre,assume dynamic viscosity of the oil 0.8 N-S/m2 and shear stress at y=0.2 m is k times shear stress at y=0.3
ANS= K=2.33
Q(UPAC). IN a three plate system having area A and two plate are stationary and one plate is moving with the velocity 'v' and determine the condition of the position by assuming viscosity coefficient liquid filled in a 'y'gap and viscosity coefficient liquid filled in a remaining gap and assuming distance between stationary plate is "H"
(1) force are equal(F1 =F2)
Q. A plate of 0.4 m2 area slides down at the constant velocity 2 m/sec and the weight of the plate 400 N, the dynamic viscosity of the oil 2 poise and the oil is lubricate below the plate determine the thickness of lubricate film of oil inclined surface at 30°from the horizontal
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