Density/ mass density(¶)>episode=5>specific gravity(G)>episode=6>fluid mechanics>theory with numerical
Fluid property
1. Density/ mass density(¶)√density=mass/volume
√density property represent denseness of the system
√unit- S.I- kg/m3
C.G.S- gm/cm3
NOTE:-
√density of water=1000 kg/m3(S.I)
(1000×1000)/106gm/cm3(.C.G.S)
1m=100cm
√density of Hg(mercury)=13600 kg/m3(S.I)
density of Hg(mercury)=13.6gm/cm3(.C.G.S)
√density of sea water=(1020 to 1030)kg/m3(S.I)
√density of air=(1.20 to 1.25)kg/m3(S.I)
Q.density of the water in american unit kg.s2/m4
a) 1000
b) 101.9
c) 100
d) 10.19
ANS=(b) 101.9
1. Mass of liquid
2. Weight of liquid
3. Specific volume
ANS=1. Mass of liquid=1.6 kg
2. Weight of liquid=15.696 kgm/s2
3. Specific volume=1.25×10-3 m3/kg
Fluid property2.specific gravity(G)
√specific gravity(G) is measured by Pychometer/hydrometer√specific gravity(G)=density of fluid/density of standard fluid
√standard fluid=(a) liqui>water>1000 kg/m3(S.I)
(b) gas>air>(1.20 to 1.25)kg/m3(S.I)
√specific gravity(G) has no unit and no dimension
◆G<1--- fluid is lighter than water
◆G=1--- fluid is water
◆G>1--- fluid is higher than water
Q.determine the specific gravity(G) of mercury(Hg) in S.I and C.G.S unit.
ANS=G=13.6(in s.i unit)
G=13.6(C.G.S unit)
√ specific gravity(G) and density(¶) numerical value is same in C.G.S measurement system
¶ in S.I =(G×1000)kg/m3
¶ in CGS=(G×1)gm/cm3
Q. If the specific gravity 0.8 for liquid A and volume of liquid A in cylindrical vessel is 3L then determine the following parameter.
1. Density
2. Specific volume
3. Mass
4. Weight
ANS=1. Density=800kg/m3
2. Specific volume=1.25×10-3m3/kg
3. Mass=2.4 kg
4. Weight=23.544 N
Comments
Post a Comment
please do not enter any spam link in the comment box